I'm going to take a shot at this, if I understand this question correctly.
I'm assuming this is a single phase AC ballast running at 110 V.
What is commonly talked about is V x I = W....that is Volts x Amps = Watts. However, what is left out of this simply formula, when talking AC volts, if "power factor". Think of this as volts lost or dissapated and not involved in the work. I'm going to guess that this power factor was different from the old dual ballast versus the newer two single ballasts. I hope this makes some sense. Here's the actual formula for AC:
I(A) = P(W) / (PF × V(V) )
I = Current in amps
P= Power in watts
PF = Power Factor (a number less than 1)
V = Voltage in volts.