If I have my blues at 60% and my whites at 30%, and I drop one by 10% and raise the other by 10%, will the par change or should it be equivalent?
"PAR" (Really PPFD) by definition measures the photon counts in all wavelengths from 400-700nm treating each "band" as equal.
Unfortunately life isn't so equal..so as mentioned above assuming your diode efficiency (photons/watt or photons/%) is equal between the 2 your "PAR"s should be equal with what you did BUT not all wavelengths have the same effect as others.
The term many use for this is "PUR" Phototsynthetically useable radiation.
PUR will differ between diodes with different spectrums i.e white vs blue.
So assuming your whites are lower PUR vs blue you aren't exactly equally changing things..
Example illustrating "pur" difference, sorry about the fuzzy chart.
Using high k whites (well low k as well but the "PUR" is in the red range but let's not complicate this too much) you won't be changing PUR by too much since the diodes are blue w/ little converting phosphors but you will change it.
What a say 10% loss (not a hard number btw) in pur with a 10% increase in output and a 10% loss on the blue side does is...
err..............questionable.
Regardless of what one grows large changes in spectrum is never a "good thing" and stability is king..
If you are going for a look thing then just as mentioned do it slow and keep in mind increasing white w/ a blue decrease isn't exactly equal in term of photosynthesis as currently understood but the difference applied equally and slowly shouldn't do "much"
You could get "fancy" and increase whites by 1X Pur factor of a 1 decrease in blues but that involves a lot of guessing.
YMMV..
Life gives few guarantees but knowing the differences gives one a shot...