Dilution Calculator Question

[Iinux]

It's honestly been a while since I've done much chemistry (or algebra), and thought I'd ask before doing.

I have a solution that I am currently dosing .25ML of every day, in the end I am wanting to dose 5ML of the solution. I am trying to figure out the amount of RODI water I will need to add in order to make this dilution goal. A bit of extra information about this would be dosing is the a,b,c,d red sea trace-colors.

Since 5ML is 20x(.25ML), would I simple do 1:20, so 1Part(Solution):20Parts(RODI)?

My end Goal being 800ML(The Container) so I would need the following calculations...
x=Amount of doses
1/5ML=x/800ML
5ML per dose, 800ML Container
160(5ML Doses) for 1 Container
y=Total Amount of Solution
z=Total Amount of RODI water
This is where I get lost...
(.25ML(y))x(4.75ML(z))= 800ML
I just simply forget how to solve for y or z when they are in parentheses first. Or am i completely off?

My grammar sucks too. I'm sorry

 

[Randy Holmes-Farley Verified Community Expert]

If you have 0.25 mL and really want that distributed in 5 mL for dosing, you'd dilute it up to 5 mL by adding 4.75 mL of water.

If you want to make 800 mL of that same concentration, you'd use:

800/5 x 0.25 mL = 40 mL of the starting fluid plus 800-40 = 760 mL of RO/Di.

 

[Iinux]

Thank you so much!
Over thought it like usual lol

 

[Randy Holmes-Farley Verified Community Expert]

lol

You're welcome.

Happy reefing.