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It also depends on how
Many LEDs you plan in running and at what intensity
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You don't need optics, leds already have built in optics of 120 degrees. Just place the unit right over the water and don't hang it up 5 feet up like some do. I'm not using optics and my fixture is a foot up and still burning all my corals so imagine if I had optics.
Hey Mai, 160 LEDs is craziness. I have 108 over my 265 gallon and they aren't running at full power. I personally think optics are a wise choice, without them you have too much light going outside your tank vs focused inside. I have a 30" deep tank and use 60 degree optics, they sit about 8" above the water. The unit is only 6" wide and the tank is 24" wide, but the coverage from front to back is excellent. I also have 6 red and 6 green LEDs that don't have optics in order to avoid banding / spotlights of red/green. Of course if you have 160 LEDs then you might not have to use optics, but optics will make your unit more efficient. Is this a current unit or one you are building?
You don't need optics, leds already have built in optics of 120 degrees. Just place the unit right over the water and don't hang it up 5 feet up like some do. I'm not using optics and my fixture is a foot up and still burning all my corals so imagine if I had optics.
Here are the numbers:
120° optics (60° coming off of center) equals 41.56" spread on the sandbed at 24" above sand and a 51.96" spread at 30" above sand. So one LED without optics will spread over 83" on the sandbed at 24" above the sand. Now that is one deep tank.
60° optics equals 13.85" spread at 24" above the sand and 17.32" spread at 30" above the sand. So one LED with 60° optics covers 26" at 24" off the sand.
I will stand by what I said above.
Here are the numbers:
120° optics (60° coming off of center) equals 41.56" spread on the sandbed at 24" above sand and a 51.96" spread at 30" above sand. So one LED without optics will spread over 83" on the sandbed at 24" above the sand. Now that is one deep tank.
60° optics equals 13.85" spread at 24" above the sand and 17.32" spread at 30" above the sand. So one LED with 60° optics covers 26" at 24" off the sand.
I will stand by what I said above.
What you said above and here is still wrong, if you actually do the math, with the law of sines you will determine that max spread of 120 degree optics at 24" off the sand in TOTAL is 24", the same at 30" off the sand bed in total is 30" of spread. Please actually do the math before throwing out false numbers. If you want to know how to actually figure this out feel free to ask. I'm happy to help.
I dislike arguing over forums, but I feel the need to respond so that the truth is out there. What I posted is the math based on sines. That is why those numbers are precise and not false as you are saying. Here are a few links that will actually do the math for you if you are struggling:
Right Triangle Angle And Side Calculator
Triangle Calculator

