as I stated in the following humble fish..in a sterile tank... it just talks about an initial dose which seems high to me. it says NOTHING ABOUT DAILY DOSING, other than replacement of the med after a water change with no given amounts so the replacement amount was my guess on how much to use as a replacement dose. so let's keep this simple. I do love learning about this but need to ensure i get it right. today is day two in my qt setup.
ok here is what i get when i do the math.
Measure (in inches) the length, width and height of the water inside the aquarium from the top of the gravel layer to the water’s surface, and inside the glass front to back and side to side. Multiple these three numbers to get the gross volume in cubic inches and then divide by 231 to determine the volume in gallons (there are 231 cubic inches in a US gallon).
- 9g ( I don’t fill my qt to the top)
Deduct an estimated percentage for tank decorations. If you are unsure, the decorations in a typical marine aquarium with artificial coral and rock displace about 15% of the water volume, so you would multiply the gross volume from step 1 by 0.85
Use the same technique to measure the volume of the gravel layer (if any), but multiply the result by 0.30, as only about 30% of the gravel layer is water, the rest of the volume is the gravel itself.
Use the same technique to measure the
volume of the sump (if any).
Except for very large systems, the amount of water contained in the filtration system is inconsequential, but you might want to add a couple of gallons to the estimate if the tank uses a large canister filter.
Add these measurements together to arrive at the estimated net aquarium volume in gallons.
Once you have estimated the aquarium system volume, multiply the number of gallons by the target dose of the drug (in mg/l or parts per million). Dividing this by 266 will give the number of grams of medication that needs to be added to the water.
Qt tank is a sterile tank with no biofilter
normal dose to be used as a quarantine preventative (not for active diseases) 10mg/l
9g x 10= 90
90/266 = 0.34 grams
normal dose for treating most protozoan infections at 15mg/l
9g x 15= 135
135/266 =0.51 grams
Normal initial dose attempting to eradicate difficult-to-treat infections at 20 mg/l
9g x 20=180
180/266= 0.67 grams
Replacement medication during a 2 Gallon Water change
normal dose to be used as a quarantine preventative (not for active diseases) 10mg/l
2g x 10= 20
20/266 = 0.075 grams
normal dose for treating most protozoan infections at 15mg/l
2g x 15= 30
30/266 =0.112 grams
Normal initial dose attempting to eradicate difficult-to-treat infections at 20 mg/l
2g x 20=40
40/266= 0.150 grams
so my initial dose of .40 grams is safe because I'm in between preventative and infections (imo) and I will only add new meds after a water change. since I can find no solid math on degradation. thoughts?