This is dependent on velocity; the smaller the pipe the faster the velocity and vice verrsa. Q=v*A where Q is flow, v is velocity, and A is cross sectional area.
So 4200GPH (308in^3/s) in a 1" (0.25pi=0.785in^2) pipe would have a velocity of 308in^3/s / 0.785in^2 = 392 in/s =32.7ft/s
but 4200GPH (308in^3/s) in a 2" (1pi=3.14in^2) pipe would have a velocity of 308in^3/s / 3.14in^2 = 98.0 in/s =8.17ft/s
The greater the velocity the greater the forces are acting on the pipes. I'm not sure what the optimum velocity is but in my system I have two 1" pipes working at about 500GPH each. Which is only 3.41ft/s
A 3" pipe would get you 3.63ft/s with a flow of 4200GPH