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Ok, I've been following along with the thread, trying to understand it.. ha
1. GFCI with no grounding probe - the gfci will not trip/cut off the circuit if something is leaking electricity unless it has somewhere else to go (ie complete the circuit via a grounding probe, me sticking my hand in the tank, etc). So in other words, if there is stray voltage or electricity, whatever you call it, in my tank, the GFCI won't trip until I stick my hand in the tank and I'm properly grounded. It should trip pretty quick so I'm not electrocuted?
2. GFCI with grounding probe - the grounding probe allows the stray electricity "another way" out of the tank, and the GFCI senses this as soon as the problem occurs and it shuts off power.
Are my assumptions correct as to this? The whole reason I installed a gfci is for my safety. Don't want to be electrocuted.
We still don't know if the grounding probe is good for the fish/coral. vs just having stray voltage, I've read articles arguing both sides and both claim better health.
Not unless there is a bad device, stray voltage isn't being sucked from the source it's induced by that stuff working. So stray voltage current would be an addition . It requires diverting some of the 120 volt supply to trigger a gfci. Don't know if that makes sense, but u can actually build a device to put next to a line with current flowing and draw power from the "stray induced voltage". I didn't see any ill effects before either I was just new so I was told it was the right thing to do. People had successful aquariums before gfci's or grounding probes were around. Just saying
Here is my best effort at explaining the volts thing.
Let us pretend I am a gold miner. Me and my partners have a long sloose box and I am lifting five gallon buckets at a steady rate and pouring water down during my shift of doing that.
My shift ends and one of my partners takes over and he is much bigger and stronger than I and he can handle the 10 gallon buckets we purchased for him to use.
Now we have more water running down the sloose box. His bigger muscles are voltage. We are getting more water because he has bigger muscles. This more water is more current. His muscles aren't going anywhere and aren't straying. His voltage is still at the top of the hill pouring buckets into the sloose. Voltage does not stray. Shorts which in this case would be leaks in the sloose box would leak current and so current does stray.
Here is my best effort at explaining the volts thing.
Let us pretend I am a gold miner. Me and my partners have a long sloose box and I am lifting five gallon buckets at a steady rate and pouring water down during my shift of doing that.
My shift ends and one of my partners takes over and he is much bigger and stronger than I and he can handle the 10 gallon buckets we purchased for him to use.
Now we have more water running down the sloose box. His bigger muscles are voltage. We are getting more water because he has bigger muscles. This more water is more current. His muscles aren't going anywhere and aren't straying. His voltage is still at the top of the hill pouring buckets into the sloose. Voltage does not stray. Shorts which in this case would be leaks in the sloose box would leak current and so current does stray.
This and the previous post are riddled with errors, no offense but most of what you said disagrees with electromagnetics. If u have a voltage and a resistor and a ground you have current flowing.
No, you have voltage at both ends of a battery, and can be read it with a meter. But if it is not wired into a circuit and connected together it does not have current flowing. A circuit with a switch turned off has a ground and a "voltage" but has no current flowing. Having voltage does not mean you have current, it means you have a potential for current.
Please name those "riddled with errors".
After thinking about it I suppose you could have any voltage with no current by rearranging the equation.
I/V = R
If you set I = 0, then R = 0, and V can equal any number because zero divided by any number is zero. I think this might an undeterminant d system though because it can be rearranged to
I/R = V
Which will give 0/0 which, I'm not positive but I believe is indeterminate. I have to check my calculus book. But this would suggest that I and R can not be zero if V contains any value.
Thinking about it even more, and thinking about what ohms law is (strictly from a mathematical standpoint)...it is a physical LAW that provides a linear relationship to mathematically explain the relationship between current and voltage experimentally observed across circuits. Resistance is a constant of proportionality that describes the relationship between current and voltage, two controlled inputs. Because of this relationship, you could never physically have a zero resistance further making it impossible to have voltage without a current without a voltage without a current and vice versa. After all current is defined through ohms law, and then physically explained as the backward low of electrons through the circuit...


