3.2-3.4v, 700ma, 3w. I understand with them in series i add up the watts to get the total wattage. But what i cant fig out is the voltage. Everything i read says 12 or 24v, dont i need to get a driver that puts out 3.2 volts?
You got the help on the voltage thing..but keep in mind that the diodes you bought AND the ones still good can vary quite a bit..
But getting to the Wattage thing.............above is incorrect.
3.4 x 700mA =2.38W each..3W is more of a "class" thing sort of telling you max wattage..
most BB drivers are 550mA so 3.4(actually slightly less at that mA ) x .550 =1.87 W
55 x 1.87W = 102w not 165W
Meanwell does make some large DC voltage drivers but most fall in the "out of range" for one reason or another.
The bigger ones do have an "AB" series which is dimmable (b) and you can adj the current (a) but most apper to be special order..
normally you can just get dimming OR current adj.
There may be others since Meanwell makes a heck of a lot of "stuff"..
Inventronics made some more equivalent to bb drivers but hard to find..
On continuity/diode/low Ohms a digital VOM "usually" will dimly light A(1) diode w/ the correct polarity..
Testing many in series is a bit different.
You can use like 9v battery to test 2-3 in series..
you can build a test "driver".. i.e meanwell LDD-HW (LW) w/ low mA and a power supply.
Voltage max of ps will determine how many in series one can test...How few is one (V(f) needs to be greater than driver minimum which I believe is 2V-ish ..
i.e 24/3.4 = 7
Also keep in mind 7 at 350mA will test "bright"..so don't stare at them..
HLG-120H-c1050(AB)
"Best fit" if you can find it..
74-128V
525-1050mA current
https://
www.meanwell.com/Upload/PDF/HLG-120H-C/HLG-120H-C-SPEC.PDF