It gets a bit more complicated than that.
Each channel can have its own current output.
Like a uv or violet driven at 350mA while the cree blue channel can be driven at 1200mA.
Made up numbers for demonstration purpose only.
Unless 1) manuf releases numbers or 2) you measure amperage yourself ( not as easy as it sounds as you generally measure " in- line" or 3) you find the driver ic, find the spec sheet and with the information contained you can identify the current set resistor ( some even use more than one resistor) value and calculate the output current, again from the driver spec sheet.
This is for commonly used driver ic's and may not always be that "easy".
2 and 3 involve disassembly of the light unless the drivers are remote which is uncommon.
Some programs may list watts and in that case you can measure voltage across the led string. Usually much easier or estimate using the led model (IF known) and get a guessimate using w = v x a.
20 rb in the xr-15 g5 blue 37.3 watts
Even this is tricky. Most rb diodes have a v( f) of around 2.9-3.6 v at normal drive currents
20 in series probably exceeds the power supply voltage so it could be broken into 2 strings of 10 each.
1/2 of 37.3 is 18.6w approx.
At say 3v is 30v
18.6 = 30 x XA
620mA....sounds reasonable eh.
Most "5w" diodes are just 2 "3w" diodes in series or parallel btw. They will be driven at the same current as you would a 3 w diode.
Say 3 x .620 = 1.86 ( 3w class) watts or 6 x .620 = 3.72 ( 5w class) watts.
The old days of pushing leds to their class limits is probably over. Lessons learned.
Of course none of that shows efficacy of the diodes.
Watts and a par meter could do that.
Another example using normal white diodes.
With a diode that pumps 150 lumens per watt vs one that pushes 75 l/w
At equal watts one has double the par.
Watts, drive current, string voltage..mostly irrelevant to par measurements unless you are building one.
Chart like this one can guesstimate drive current pretty easy and efficacy.
Each manuf should have one. Getting them to cough it out is another story.
CREE Photo red is approx 1.95 to 1.99v
1 is listed at 5w so I'd assume 2 in series in 1 diode 4V.
1250mA. BUT crees vf is 1.99v?
Assuming 2 in parallel
2v 2.5w each diode, 1250mA.

CREE lists photo red it at 1.99v 1500mA ( split 2 ways internally 750mA each diode) max current sooo
2 x 1.5= 3w.
Pro has 2 of these and lists 7.3w.
That would be 7.3 = 4v x X A
1825mA
2 in parallel
3.65w at 2v 1825 again. Exceeds CREE photo red x lamp rating of 1500mA
Soo what is the issue here?
Wrong v(f).
3.65w @2.5v = 1460mA
1460mA
5v ( 2 in series) and 7.3w = 1460mA
They really push the limit on these.
Redoing the single reduces drive current to 1000mA.
Lime 700mA @ 2.75v recommended specs
1.93watts each
Recommended max drive current of 1000mA
2 @ 6w probably also pushes the limit.