If we rewrite the vinegar equation in steps, we see that while the H+ release instantly drops pH, the subsequent conversion of the acetate to CO2 only produces half the amount of CO2:
CH3CO2H --> H+ + CH3CO2- (that lowers pH instantly by one H+ per acetic acid))
then we oxidize the acetate:
CH3CO2- + 2O2 --> 1CO2 + 1 HCO3- + 1 H2O
That oxidation has only one CO2 added, instead of 2. The HCO3- does not have much effect on pH since it mostly stays as bicarbonate.
Thus, half of the vinegar pH drop is shown instantly, and about half is shown later when CO2 is made, while vodka does it all later.