Pump flow rate questions (physics)

This is false, see below.




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Ok, fair enough. I'll get back to my physics classes.
 
Correct, if we are assuming that the length of the pipe is the same in each tank that's above the water
Well, it wouldn't be, right? The display is in the same location let's say 14 ft above on the second floor, so let's also say that the reservoir is 30" deep. If you place the pump at the bottom of that 30" vs the top of that 30" you've knocked off 2 feet or so of plumbing, which in my mind makes for less loss...
 
size of pipe, length, fittings and typ of pipe [corrugated or smooth] all effect head pressure
 
Well, it wouldn't be, right? The display is in the same location let's say 14 ft above on the second floor, so let's also say that the reservoir is 30" deep. If you place the pump at the bottom of that 30" vs the top of that 30" you've knocked off 2 feet or so of plumbing, which in my mind makes for less loss...
Normally you would be right, however in this case the head pressure doesn't begin until the water rises above the tank level it's sitting in.
 
Well, it wouldn't be, right? The display is in the same location let's say 14 ft above on the second floor, so let's also say that the reservoir is 30" deep. If you place the pump at the bottom of that 30" vs the top of that 30" you've knocked off 2 feet or so of plumbing, which in my mind makes for less loss...
head pressure starts at water surface
 
OK after revisiting this I stand corrected. @KStatefan and @Sean Clark are right, my apologies to you both. Flow volume will remain the same, velocity will be reduced.

No apologies needed this forum is here for people to learn. I am do not know much about anything reef related except water flow.
 

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