I'm kinda lost too

. Let's redo the math.
Since your recommendation is doubling Balling Part C, then:
- 594 grams of baking soda = 163 grams of sodium = 19.5 grams of magnesium needed to offset sodium chloride buildup (12% of 163 grams).
- Balling Part C has 3350 mg/L of magnesium. So that’s 3350 x 3.78 x 2 (2 gallons added for every 1 gallon of Recipe #1) = 25.3 grams of magnesium. That would be 15.5% of 163 grams, which exceeds the 12%.
To calculate the additional magnesium needed for coral consumption, we actually need to subtract the excess from Balling Part C (25.3 - 19.5) / 47 g/L = 123 ml of Part C from your recipe needs to be added on top of Balling Part C.
Correct me if I’m wrong,
Thanks!