Sep 12, 2020 #1 C csb123 Well-Known Member View Badges Joined Apr 24, 2016 Messages 779 Reaction score 770 Rating - 0% 0 0 0 It is so simple, but I don’t want to screw it up. I have 2.0 molar hydrochloric acid. I need to dilute it down to 0.1 molar? How many grams/mL do I add to make 1L?
It is so simple, but I don’t want to screw it up. I have 2.0 molar hydrochloric acid. I need to dilute it down to 0.1 molar? How many grams/mL do I add to make 1L?
Sep 12, 2020 #2 EMeyer Valuable Member View Badges Joined Jan 23, 2016 Messages 1,148 Reaction score 1,884 Rating - 0% 0 0 0 csb123 said: It is so simple, but I don’t want to screw it up. I have 2.0 molar hydrochloric acid. I need to dilute it down to 0.1 molar? How many grams/mL do I add to make 1L? Click to expand... Use the dilution equation, C1 * V1 = C2 * V2 Click to expand... Substituting in your numbers, 2M * X ml = 0.1M * 1000 ml X ml = (0.1M * 1000 ml) / 2M X = 50 ml Click to expand... so 50 ml of your 2M HCl plus 950 ml of RODI. And remember, always add acid to water, not the other way around!
csb123 said: It is so simple, but I don’t want to screw it up. I have 2.0 molar hydrochloric acid. I need to dilute it down to 0.1 molar? How many grams/mL do I add to make 1L? Click to expand... Use the dilution equation, C1 * V1 = C2 * V2 Click to expand... Substituting in your numbers, 2M * X ml = 0.1M * 1000 ml X ml = (0.1M * 1000 ml) / 2M X = 50 ml Click to expand... so 50 ml of your 2M HCl plus 950 ml of RODI. And remember, always add acid to water, not the other way around!
Sep 12, 2020 #3 OP OP C csb123 Well-Known Member View Badges Joined Apr 24, 2016 Messages 779 Reaction score 770 Rating - 0% 0 0 0 Thank you friend. Just needed to be certain of the math
