Ok, we got this!
The reagent
here lists 330 test for a 50 ml sample at a KH of 8. The reagent is 1000 ml, so that means 3.03 ml per test.
The thread below shows that 0.02N reagent in a 8.0 KH, 50 ml sample, requires 7.15 ml of reagent.
Hi everyone, i see there are a lot of diy's for alkatronic, kh guardian etc but none for the kh keeper. has anyone successfully created a homemade reagent with HCL?
www.reef2reef.com
So it looks like they are either using a 'custom' normalization (not off the shelf), or they have you dilute it a bit less than 0.04N. I don't see any place to access the instructions for their reagent. It may just be an off the shelf acid standard, like 0.1N, and diluted less than the other units use (4:1).
I read through their quick start guide. It does not mention diluting the reagent at all. So I think they sell it ready to use. Hmm, a bit of a waste shipping all that fluid. No matter, you can simply make your own using an off the shelf acid standard.
The odds are that I will probably mess up the calculation, so you may need one of the chemistry folk to double check it, but I would calculate it at:
7.15 ml / 3.03 ml = 2.3597359736 * 0.02N = 0.0471947195N <-- this is the normalization that you require of reagent (acid)
Ok, now let's see if we can calculate a dilution to get you there.
A dilution of 1:1.1188811189 gets you to a normalization of 0.0471947195N, which is what you need (if my calcs are right).
To do that multiply your 0.1N acid weight by 1.1188811189 to find out how much RODI you need to dilute it with.